Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower


koi h tya? ​

Answer 1

Answer:

17.320 m

$\underline{\bf{Explanation\::}}$

$\sf\color{red}Refer \:the\: attached \:figure$

$\sf\color{red}AB = \:Height \:of\: tower$

$\sf\color{red}BC =\: 30 m$

$\sf\color{red}∠ACB\: = \:30°$

$\sf\color{red}In\:ΔABC$

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}}$

$\boxed{\bf{17.320\:=AB \:17.320\:=\:AB }}$

➦Hence The height of tower is 17.320 m

Answer 2

Answer:

represent the given situation using a figure

Angle of elevation on the top of a tower from a point on the ground=30°

Distance of point(c) on ground from the foot of tower=30m

10√3m