The angle of elevation of the top of a tower from a point on the ground, which
is 20 m away from the foot of the tower, is 30". Find the height of the tower.
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Answer:
Let AB be the height of the tower and C be the point .
In rt.△ABC,
tan30° = AB/BC
AB = BC tan30°
= 20/√3 = 20/√3 × √3/√3
= 11.56 m
Therefore the height of the tower is 11.56 m.
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