Question

the angle of elevation of the top of a tower from a point on the ground which is 30m away from foot of tower is 30° find hight of tower

Answer 1

here is your answer by Sujeet,

Given that,
Angle of elevation of the top of a tower on the ground =30m

$$Foot of tower=30°
Tant theta=p/b
1/√3=p/30
p=30/✓3 * √3/√3
p=10√3

then,
Height of tower=10√3 metre

that's all
Sujeet,

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Answer 2

Answer:

In ∆ ABC,

tan ∅ = Opposite side / Adjacent side

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.