Question

The angle of elevation of the top of a tower from a point on the ground , which is 30m away from the foot of the tower , is 30 degree . Find the height of the tower .

Answer 1

Given, angle of elevation = 30°

Distance of point from foot of the tower = 30 m

To find, height of the tower.

We know that tan (any angle) = opposite side / base

Therefore, tan 30° = Height of tower / distance of point = Height of tower / 30

We know that tan 30° = 1/√3 = Height of tower/30

Height of tower = 30/√3 = 10√3 m

Hope I helped!

Answer 2

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}} = AB$

17.320 = AB

Hence The height of tower is 17.320 m