Question

the angle of elevation of the top of a tower from two points at a distance of 4m and 9m from the base of the tower and in the same straight line with it are complementary. prove that the height of the tower is 6m

Answer 1

Answer:

P and Q are the points at distance of 4m and 9m respectively. From fig, PB = 4m, QB = 9m. Let angle of elevation from P be α and angle of elevation from Q be β. Therefore, AB = 6.

Step-by-step explanation:

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Answer 2

Hence the height of tower is 6m...