the angle of elevation of the top of a tower from two points at a distance of 4 m and 9m from the base of a tower and in the same straight line with it are 60 degree and 30 degree find the height of the tower
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4√3 is the height of the tower.
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Answer:
1st:
tan0=height /base
tan 60=h/4
^3=h/4
h=^3*4
^denotes square root
0 denotes theta
Step-by-step explanation:
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