Question

the angle of elevation of the top of a tower is observed to be 60 degree at a point 40 m above the first point of a observation the elevation is find to be 45 degree . find the height of the tower.​

Answer 1

Answer:

To find → Height of tower (AB)

Let AB =h m

In △ABC, by Trigonometry

tan60∘=BCAB

3=BCh⇒BC=(3h)m

Since BCDE is a ||gm, so BC=DE and CD = BE

∴DE=(3h)m; BE=40m

Now in △ADE

tan30∘=DEAE

31=3hh−40

h=3h−120

2h=120m

h=60m

Height of tower = 60 m.

To find → Horizontal Distance from point of observation (BC)

BC=3h=360

Step-by-step explanation:

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