the angle of elevation of the top of a vertical Tower from a point P on the ground is 60°. At a point Q vertically above P, angle of elevation is 45 degree.
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The angle elevation of the top Q of a vertical tower PQ from a point Xon the ground is 60 degree . at a point Y, 40 m verticaaly above X, the angle of elevation is 45 degree . find the height of the tower PQ and the distance XY.
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Let the height be EC
Let the the angle EAD be 45° and the angle EBC be 60°
Let EB be x m and in reactangle ABCD we know that opposite sides are equal: AB = CD = 10 m and BC = AD
Now,
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★ Height of the tower will be :
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