the angle of elevation of the top of building from the foot of the tower is
300
and the angle of elevation of the top of the tower from the foot of the
building is 600
. If the tower is 50m high, find the height of building.
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Answer:
Given height of tower CD=50m
Let the height of the building, AB=h
In right angled △BDC,
⇒ tan60
o
=
BD
CD
⇒
3
=
BD
50
⇒ BD=
3
50
m
In right angled △ABD,
⇒ tan30
o
=
BD
AB
⇒
3
1
=
3
50
h
∴
3
1
=
50
3
h
∴ h=
3
50
=16.66m
∴ The height of the building is 16.66m.
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