Question

The angle of elevation of the top of the building from the foot of the tower is 30° and the angle of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.

Answer 1

Answer:

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Answer 2

Given :

Height of tower CD = 50m

Let the height of the building, AB = h.

In right angled Δ BDC,

=> tan 60° = CD/BD

=> √3 = 50/BD

=> BD = 50/ √3 m

In right angled  Δ ABD,

=> tan 30° = AB / BD

=> 1/√3 = h/50/√3

Therefore,

1/√3 = √3h/50

Therefore, h = 50/3 = 16. 66 m

The height of the building is 16.66 m .