The angle of elevation of the top of the building from the foot of the tower is 30° and the angle of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.
Answers
Answered by
0
Answer:
I don't know Friend And How are you
Answered by
0
Given :
Height of tower CD = 50m
Let the height of the building, AB = h.
In right angled Δ BDC,
=> tan 60° = CD/BD
=> √3 = 50/BD
=> BD = 50/ √3 m
In right angled Δ ABD,
=> tan 30° = AB / BD
=> 1/√3 = h/50/√3
Therefore,
1/√3 = √3h/50
Therefore, h = 50/3 = 16. 66 m
The height of the building is 16.66 m .
Similar questions