A vertically straight tree, 15m height, is broken by the wind in such a way that its top just touches the ground and makes an angle of 60° with the ground. At what height from the ground did the tree break?
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bhai ye kya question h
I don't no
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The tree broke at 1m height from the ground
Step-by-step explanation:
We find that ABC is a triangle with BC as the hypotenuse and angle B is 90 degrees. Given that angle C is 60 degrees. Let x be the height from the ground at which the tree broke.
AB = opposite = x
AC = hypotenuse = 15-x
So Sin 60 = Opposite/ hypotenuse = x/(15-x)
√3/2 = x/(15-x)
√3(15-x) = 2x
15√3 - √3x = 2x
15√3 = (2+√3)x
Therefore x = 15√3 / (2+√3)
= 15√3 * (2-√3) / 4+3
= 30√3 - 45 / 7
= 52-45/ 7
= 7/7
= 1
So the tree broke at 1m height from the ground.
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