Question

The angle of elevation of the top of the tower AB from a point C on the
ground, which is 60 m away from the foot of the tower, is 30°, as shown in
Figure-2. Find the height of the tower.
30°
60 m
Figure-2​

Answer 1

Step-by-step explanation:

tan 30° = AB/BC

1/√3 = AB/60

AB=60/√3

ratinalosing

AB = 60/√3×√3/√3

AB=60√3/3

AB= 20√3m