Question

the angle of elevation of the top of the tower from a point on the ground which is 30 M away from the foot of the tower is 30 degree find the height of the tower

Answer 1

Let hight of the tower be PQ. And the point be on S.

Distance between QS = 30m

tanS = Perpendicular/Height

tanS = PQ/30

1/√3 = PQ/30

30/√3 = PQ

PQ = 10√3

Answer 2

Step-by-step explanation:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.