the angle of elevation of the Top of the tower from a point on the ground which is 30m away from the foat of the tower ,is 30° find the height of the tower
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Step-by-step explanation:
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Step-by-step explanation:
In ∆ ABC,
tan ∅ = Opposite side / Adjacent side
tan 30° = AB/BC
1/√3 = AB/30
30/√3 = AB
AB = 30/√3
Now, Multiplying numerator and denominator by 3 we get:
AB = 30/√3 × √3/√3
AB = 30√3/3
AB = 10√3
Therefore, the height of the tower is 10√3.
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