Question

The angle of elevation of the top of the tower from two points distance a and b from the base of tower (a>b) are 30degree and 60 than height of tower is

Answer 1

Answer:

Height of Tower = √ab

a/√3 = b√3  = Height of Tower

Step-by-step explanation:

The angle of elevation of the top of the tower from two points distance a and b from the base of tower (a>b) are 30degree and 60 than height of tower is

Let say Base = O

Top of Tower = D

a & b are points of Distance a & b from O

Tan 30  =  OD/OA

=> 1/√3 = OD/a

=> OD = a/√3

Tan 60 = OD/OB

=> √3 = OD/b

=> OD = b√3

a/√3 = b√3 = Height of tower

=> a = 3b

OD * OD = (a/√3)b√3

=> OD² = ab

=> OD = √ab

Answer 2

Height of tower = √ab

a/√3 = b√3 = height of tower

let say base = O

top of tower = D

a and b are points of distance a and b from O

tan 30degree = OD/OA

1/√3 = OD/a

OB = a/√3

tan 60degree = OD/OB

√3 = OD/b

OD = b√3

a/√3 = b√3 = height of tower

a = 3b

OD*OD = (a/√3)b√3

ODsquare = ab

OD = √ab anssss