Question

The angle of elevation of the top of the tower when observed from a point distance 90m from the foot of the tower is 60° then find the height of the tower ?

Answer 1

Let the height of the tower =hm

and the distance between building and tower =xm

Now, in △AED,

⇒tanx=

a

60

⇒atanx=60⟶(1)

Again, △BAC,

⇒tanx=

a

(h−60)

⇒atanx=h−60⟶(2)

From equations (1)ξ(2), we get

⇒h−60=60

⇒h=120

∴ Height of tower 120m

Hence, the answer is 120.