The angle of elevation of the top of tower from a point on the ground is 60degrees . From another point 10m vertically above the first ,its angle of elevation is 45 degrees.Find the height of the tower.
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let the height be h m
also, bc=ed
then tan 60= h/bc
√3=h/bc
bc=h/√3---1.
now tan 45= h-10/ed
1=h-10/h/√3
h=√3h-10√3
10√3=h(√3-1)
10√3/√3-1=h
also, bc=ed
then tan 60= h/bc
√3=h/bc
bc=h/√3---1.
now tan 45= h-10/ed
1=h-10/h/√3
h=√3h-10√3
10√3=h(√3-1)
10√3/√3-1=h
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Step-by-step explanation:
Let the height be EC
Let the the angle EAD be 45° and the angle EBC be 60°
Let EB be x m and in reactangle ABCD we know that opposite sides are equal: AB = CD = 10 m and BC = AD
Now,
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★ Height of the tower will be :
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