Math, asked by SHAILENDRA9876, 1 year ago

The angle of elevation of top of a tower from a point on ground, which is 30m away from the foot of the tower, is 30°. Find the height of the tower.

Answers

Answered by nirmal123415
6
this is the answer for your question
Attachments:
Answered by BrainlyRaaz
16

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

 Tan \theta=\frac{Perpendicular}{Base}

 Tan30^{\circ}=\frac{AB}{BC}

 30 \times \frac{1}{\sqrt{3}} = AB

17.320 = AB

Hence The height of tower is 17.320 m

Attachments:
Similar questions