Question

the angle of elevation of top of an unfinished vertical building on a ground at a point which is 100 M from the base of the building is 45 degree how much height the building must be raised so that it's angke of elevation from the same point be 60degree ​

Answer 1

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Answer 2

height the building must be raised  by 73 m so that it's angle of elevation from the same point be 60 degree ​

Step-by-step explanation:

let AB be the tower and P be the point of observation making an angle of elevation 45°

let BC be the raised height so that the angle of elevation be 60°

in triangle  APB

$tan 45 = \frac{AB}{AP}$

$1= \frac{AB}{100}$

AB = 100 m

in triangle APC

$tan 60 = \frac{AC}{AP}$

$\sqrt{3} = \frac{100+X}{100}$

$100\sqrt{3} =100+x$

$100(\sqrt{3}-1 ) = x$

putting the value of √3 = 1.73

$100(1.73-1) = x$

100(0.73) = x

73 = x

BC = 73 m

hence ,

height the building must be raised  by 73 m so that it's angke of elevation from the same point be 60 degree ​

#Learn more:

A window in a building is at height of 10m from the ground. The angle of depression of a point A on the ground from the window is 30degree. The angle of elevation of the top of the building from the point A is 60degree. Find the height of the building.

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