the angle of elevation of top of mount from ground is 30* after walking 10m away from mountain angle becomes 15 .find height of mountain
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In △ CAB , we have
tan30
∘
=
AC
AB
⇒
3
1
=
x
h
⇒x=
3h
In △ DAB we have
tan15
∘
=
AD
AB
⇒0.27=
x+10
h
⇒ (0.27) (x + 10) = h
substituting x =
3h
obtained from equation (i) in equation (ii) we get
0.27 (
3h
+ 10) = h
⇒0.27×10=h−0.27×
3h
⇒ h (1 - 0.27 ×
3
) = 2.7
⇒ h (1 - 0.46 ) = 2 . 7
⇒h=
0.54
2.7
= 5
Hence , the height of the mountains is 5 km
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