the angle of Pentagon are in the ratio3:4:5:8:7find all the angles
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Hey There! This is your solution____________
Let the angles of Pentagon be 3x,4x,5x,8x and 7x.
As we know that Sum of all angles of a Pentagon is always 540°.
A/q:-
3x + 4x + 5x + 8x + 7x = 540°
Or, 27x = 540°
Or, x = 540/27
Or, x = 20°
Hence,
Angle1 (3x) = 60°
Angle2 (4x) = 80°
Now, Please Do this way and you will get the answer....
Let the angles of Pentagon be 3x,4x,5x,8x and 7x.
As we know that Sum of all angles of a Pentagon is always 540°.
A/q:-
3x + 4x + 5x + 8x + 7x = 540°
Or, 27x = 540°
Or, x = 540/27
Or, x = 20°
Hence,
Angle1 (3x) = 60°
Angle2 (4x) = 80°
Now, Please Do this way and you will get the answer....
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