Question

The angle of projection for which the horizontal range and maximum height of projectile are same will be

Answer 1

Hey !

Given:

        Maximum height of projectile, H = R

where R = Horizontal range

Maximum height attained by projectile is

Solution:            

              H = u²sin²θ/2g

Now,

       Horizontal range of the projectile

                     R = u²sin2θ/g

∴          u²sin2θ/2g = u²sin2θ/g

(or)       sin²θ/2 = 2 sinθ cosθ

(or)       sinθ/cosθ = 4

(or)        tanθ = 4

(or)            θ = tan⁻¹ 4 = 75.96° ≈ 76°

Good luck !