Question

The angle of quadrilateral are in ratio 1:1:2:5. Find each angle of the quadrilateral​

Answer 1

Given :

• Angle if quaderilateral are in the ratio of 1:1:2:5.

To find :

• Each angle of the quadrilateral.

According to the question,

Let the angles be 1x,1x,2x and 5x.

As we know that,

• Sum of all angles of a quaderilateral is 360°

➞ 1x + 1x + 2x + 5x = 360°

➞ 2x + 7x = 360°

➞ 9x = 360°

➞ x = 360° ÷ 9

➞ x = 40°

★ Value of 1x :

➞ 1x

➞ 1(40°)

➞ 40°

★ Value of 1x :

➞ 1x

➞ 1(40°)

➞ 40°

★ Value of 2x :

➞ 2x

➞ 2(40°)

➞ 80°

★ Value of 5x :

➞ 5x

➞ 5(40°)

➞ 200°

• So,the angles of a quadrilateral is 40°, 40°, 80° and 200°.

____________________

Verification :-

➞ 1x + 1x + 2x + 5x = 360°

➞ Putting the value of x is 40°

➞ 1(40°) + 1(40°) +2(40°) + 5(40°) = 360°

➞ 40° + 40° + 80° + 200° = 360°

➞ 360° = 360°

∴ L.H.S = R.H.S

Hence, Verified.

Answer 2

Answer:

Given :-

• Angle of Quardilateral = 1:1:2:5

To Find :-

Angle

Solution :-

As we know that sum of all sides of Quardilateral is 360⁰.

Let the angles be x

$\tt \implies \: 1x + 1x + 2x + 5x = 360$

$\tt \implies \: 9x = 360$

$\tt \implies \: x = 360 \div 9$

$\tt \implies \: x = 40$

Therefore

Angles will be

$\tt \implies \: angle \: 1 \: and \: 2 \: will \: be \: equal$

$\tt \: 1x = 1(40) = 40$

$\tt1x = 1(40) = 40$

$\tt \: 2x = 2(40) = 80$

$\tt \: 5x = 5(40) = 200$