the angle of quadrilateral are x, x+20,x-50and 2x find the greatest angle
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Bonjour!
According to the question the angle of quadrilateral are x, x+20 ,x-50 and 2x.
As, we know the sum of angles of quadrilateral is = 360°
So,
=> x + x + 20 + x - 50 + 2x = 360°
=> 5x - 30° = 360°
=> 5x = 390°
=> x = 78°
So, the first angle x = 78°
Second angle = 78° + 20° = 98°
Third angle = 78° - 50° = 28°
Fourth angle = 2 × 78° = 156°
Therefore the greatest angle = 156°
Hope this helps...:)
According to the question the angle of quadrilateral are x, x+20 ,x-50 and 2x.
As, we know the sum of angles of quadrilateral is = 360°
So,
=> x + x + 20 + x - 50 + 2x = 360°
=> 5x - 30° = 360°
=> 5x = 390°
=> x = 78°
So, the first angle x = 78°
Second angle = 78° + 20° = 98°
Third angle = 78° - 50° = 28°
Fourth angle = 2 × 78° = 156°
Therefore the greatest angle = 156°
Hope this helps...:)
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