Math, asked by nikhitha66, 1 month ago

the angle of the tower to the top of the tower is 60° but the height of the tower in 100 m from the tower word____​

Answers

Answered by subbarayulu7949
0

Answer:

Let AB be the tower and CD be the hill. Then, ∠ACB=30

o

,∠CAD=60

o

and AB=50 m.

Let CD=x m

In right △BAC, we have,

cot30

o

=

AB

AC

3

=

50

AC

AC=50

3

m

In right △ACD, we have,

tan60

o

=

AC

CD

3

=

50

3

x

x=50×3=150 m

Therefore, the height of the hill is 150 m.

Answered by vitex1504
0

Answer:

Given height of tower CD=50m

Let the height of the building, AB=h

In right angled △BDC,

⇒ tan60

o

=

BD

CD

3 =

BD

50

⇒ BD=

3

50metres

In right angled △ABD,

⇒ tan30

=

BD

AB

31

=

350

h

31

=

503

∴ h=

3

50

=16.66m

∴ The height of the building is 16.66m.

s

Step-by-step explanation:

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