The angle of triangle are X + 10 degree and X + 40 degree and 2 x minus 30 degree find the measure of all the angles
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Given :-
angle a = X+10
b = X+40
c = 2x - 30
ATQ
sum of angles of triangle = 180
angle a + b + c. = 180
X+10 + X + 20 + 2x - 40. = 180
4x -10 = 180
4X = 180 + 10 = 190
X = 190÷4
X = 47.5
Therefore , a = X+10
47.5 + 10
57.5
b = X + 20
47.5 + 20
67.5
c= 2x - 40
2 × 47.5 - 40
95- 40
55
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