the angle substended by the diameter in a circle is a/90 b/180 c/60d/45
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Step-by-step explanation:
To prove : ∠APB=90
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∵ We know angle subtended by an arc at centre is double the angle subtended at any point or circumference.
⇒ Angle subtended by arc AB at O= Double the angle subtended at P
⇒∠AOB=2∠APB
∵AOB is a straight line.
⇒∠AOB=180
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⇒2∠APB=180
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⇒∠APB=90
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∴ Angle subtended by arc AB or semi circle is 90
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