The angles of a cyclic quadrilateral ABCD are ∟A = 6x+10°, ∠B= 5x°, ∠c= (x+4) &∠D =3y-10°. Find x &y.
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Opposite angles of cyclic quad are 180.
LA+LC=180
6x+10+x+4=180
7x=180-14
7x=166
x=23
LB+LD=180
5x+3y-10=180
5(23)+3y=190
115+3y=190
3y=75
y=25
LA+LC=180
6x+10+x+4=180
7x=180-14
7x=166
x=23
LB+LD=180
5x+3y-10=180
5(23)+3y=190
115+3y=190
3y=75
y=25
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