The angles of a pentagon are x°, (x+20°), (x+40°), (x+60°), and (x+80°) .find the smallest angle of the pentagon is?
Answers
Answered by
235
The sum of the interior angles of a pentagon is 540
Therefore ,
x+x+20+x+40+x+60+x+80=540
5x+200=540
5x=340
x=68
Therefore the smallest angle of the pentagon = x = 68
x is the smallest angle of the pentagon is x because all the other angles are greater than x.
Therefore ,
x+x+20+x+40+x+60+x+80=540
5x+200=540
5x=340
x=68
Therefore the smallest angle of the pentagon = x = 68
x is the smallest angle of the pentagon is x because all the other angles are greater than x.
bichchu:
Why the sum of interior angles is 540
The sum of the interior angles of any polygon is (n-2)*180 , where n is the number of sides.
Answered by
84
THE ANGLES IN THE PENTAGON ARE 540
SO,
X+X+20+X+40+X+60+X+80 = 540
5X+200 = 540
5X = 540 - 200
5X = 340
X = 340 / 5
X = 68
THEREFOR THE SMALLEST ANGLE IN THIS IS X = 68
SO,
X+X+20+X+40+X+60+X+80 = 540
5X+200 = 540
5X = 540 - 200
5X = 340
X = 340 / 5
X = 68
THEREFOR THE SMALLEST ANGLE IN THIS IS X = 68
Similar questions