the angles of a quadilators are in the ratio 3:4:5:6: the largest of these angles is
Answers
Answered by
0
Answer:
120
Step-by-step explanation:
LET THE ANGLES BE 3X, 4X, 5X, 6X
THE SUM OF INTERIOR ANGLE OF A QUADRILATERAL IS 360 DEGREE
3X+4X+5X+6X=360
18X=360
X=360\18
X=20
3X=3×20=60
4X=4×20=80
5X=5×20=100
6X=6×20=120
hope it helps to you
Answered by
0
Answer:
Given the angles of a quadrilateral are in the ratio 3:4:5:6
Let the angles of quadrilateral be 3x,4x,5x, and 6x
We know that the sum of all angles of a quadrilateral is 360
∴3x+4x+5x+6x=360
18x=360
x=360
/18
x=20
Hence, the angles are:
3x=3×20
=60
4x=4×20
=80
5x=5×20
=100
6x=6×20
=120
Hence,the largest angle is 120
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