Question

the angles of a quadratrical in A.P with D=10° find the all angles of quadratrical​

Answer 1

Let the angles of the quadriletarel be a°, (a+d)°, (a+2d)°, (a+3d)°

Now,

a°+(a+d)°+(a+2d)°+(a+3d)° = 360°

=>4a°+(1+2+3)d° = 360°

=>4a°+6d° = 360°

=>4a+(6×10)° = 360°

=>4a+60° = 360°

=>4a = 300°

=>a = 75°

The angles are 75°, 85°, 95°, 105°

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