Question

The angles of a quadrilateral are 5x, 5(x+3), (6x-10) and (6x+3)
respectively. Find the value of x and (ii) each angle of the quadrilateral​

Answer 1

We know that the sum of all the interior angles in a quadrilateral add up to 360°.

=> 5x+5x+15+6x-10+6x+3=360

=> 22x=352

=> x= 16°

Therefore all the angles of the quadrilateral are:

5x=80°

5x+15=95°

6x-10= 86°

6x+3=99°

Hope it helps you....✌️✌️❤️❤️❤️☺️☺️

Answer 2

The sum of angles of a quadrilateral= 360°

Therefore,

5x+5(x+3)+(6x-10)+(6x+3)=360°

5x+5x+15+6x-10+6x+3=360°

22x+8=360°

22x= 352°

x= 16°

The angles are:

5x= 5*16= 80°

5(x+3)= 5(16+3)= 5*19= 95°

6x-10= 6*16-10= 96-10= 86°

6x+3 = 6*16+3= 96+3= 99°