Question

!
The angles of a quadrilateral are in A.P.
and the greatest angle is double the
least. Find angles of the quadrilateral in
radian.​

Answer 1

Explanation:

let the smallest term be x

and, largest term be 2x

Then AP formed= x,?,?, 2x

so, Sn= n/2 [2a+ (n-1)d]

=> sn= n/2 [a+ a(n-1)d]

=> 360°= 4/2 [x+ 2x]....[We know that → a+(n-1) d= last term= 2x]

=> 180°= 3x

=> x= 60°

Now, 60° is least angle.

= 60°= π/180° *60°

=> 60° = π/3 rad

hope this may help u........