Question

The angles of a quadrilateral are in ap whose common difference is 15 degrees. Find the angles.

Answer 1

Answer:

Step-by-step explanation:

Since are angles are in AP and common difference is 15

Let the smallest angle be a

Then other three angles = a+15 , a+30 , a+45

Sum of angles of a quadrilateral = 360

a+a+15+a+30+a+45 =360

4a + 90 = 360

4a = 270

a = 270/4 = 135/2 = 67.5

So the angles are 67.5° , 82.5° , 97.5° , 112.5°

Answer 2

Answer:

67.5,82.5,97.5,112.5,....

Step-by-step explanation:

angles are in AP and common difference is 15

Let the smallest angle be a

Then other three angles = a+15 , a+30 , a+45

Sum of angles of a quadrilateral = 360

a+a+15+a+30+a+45 =360

4a + 90 = 360

4a = 270  

a = 270/4 = 135/2 = 67.5

So the angles are 67.5° , 82.5° , 97.5° , 112.5°