Question

The angles of a quadrilateral are in AP whose common difference is 10degree. Find the angles.

Answer 1

Answer:

Step-by-step explanation:

Let these angles be

x°, (x+10°), (x+20°), and (x+30°)

Sum of all angles = 360°

x + x + 10 + x + 20 + x + 30 = 360°

4x + 60 = 360°

4x = 360 - 60

4x = 300°

x = 300/4

x = 75°

NOW THE ANGLES ARE :-

75° , 85°, 95°, 105°

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