the angles of a quadrilateral are in ap with d=10 degree.Find the angles
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the sum of all angles of a quadrilateral = 360 degree
take a=x
d=10
so,
angle 1 = x
angle 2 , 3 and 4= x+10, ×+20 and ×+30
now,
×+×+10+×+20+×+30=360
4×+60=360
4×=360-60
4×=300
×=300÷4
×=75
now substitute x=75
a=75(angle one)
a+d=75+10=85( angle two )
a+2d=75+2×10=95( angle three )
a+3d=75+3×10=105( angle four)
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