Question

The angles of a quadrilateral are in the ratio of 2 : 3:4:6. Find the measure of each angle.
The two angles of a quadrilateral are 70° and 120°. The other two angles are equal. Find the
measure of equal angles.

solve any one​

Answer 1

Answer:

Let the common multiple be x

THEREFORE, 2x : 3x : 4x : 6x

2x + 3x + 4x + 6x = 360°

15x = 360°

x = 360÷15

x = 24

2x = 2×24 = 48°, 3x = 3×24= 72°,

4x = 4×24=96° , 6x = 6×24= 144°

Are the Angles of quadrilateral.

they must be paralellogram or rhombus, so there opposite Angels are congruent.

The measure of equal Angels are 70° and 120°.

Answer 2

SOLUTION:-

Given:

The angles of a quadrilateral are in the ratio of 2:3:4:6.

To find:

The measure of each angle.

Explanation:

We know that, sum of the angles of quadrilateral are 360°

Let the angles be R.

• First angle= 2R
• Second angle= 3R
• Second angle= 3RThird angle= 4R
• Second angle= 3RThird angle= 4RFourth angle= 6R

Therefore,

=) 2R + 3R +4R +6R=360°

=) 15R= 360°

=) R= 360/15

=) R= 24°

Now,

• 1st angle,2R= 2×24°= 48°
• 2nd angle,3R=3×24°= 72°
• 3rd angle, 4R=4×24°= 96°
• 4th angle, 6R= 6×24°=144°

&

Given: Two angles of quadrilateral are 70° & 120°.

Let the first angle & second angle be R

Therefore,

=) R + R + 70° +120°= 360°

=) 2R+ 190°= 360°

=) 2R= 360° -190°

=) 2R= 170°

=) R= 170°/2

=) R= 85°

Thus,

The other two angle is 85°.