Question

the angles of a quadrilateral are x, x-10, x+30 and 2x find the angles​

Answer 1

Step-by-step explanation:

GIVEN THAT

angles of a QUADRILATERAL = x , x-10 , x+30 , 2x

We know that :

Sum of angles of a QUADRILATERAL = 360°

So,

x + (x-10) + (x+30) +2x = 360°

x + x + x + 2x +20 = 360°

5x +20 = 360°

5x = 340°

x = 68

So the angles are :

68° , 58° , 98° , 136°

HOPE IT'S HELPFUL

Answer 2

SUM OF ALL ANGLES OF QUADRILATERAL IS 360°

Given angles are x,x-10,x+30,2x

x+x-10+x+30+2x=360

5x+20=360

5x=340

x=340/5

x=68

• X=68
• X-10=58
• X+30=98
• 2X=136