Question

.The angles of a quadrilateral are x, x – 10, x + 30 and 2x, the smallest angle is equal to

Answer 1

$\huge \mathfrak \pink{♡︎ \: solution \: ♡︎}$

❥︎. The sum of quadrilateral is 360°.

So, x+ x-10+ x+30+2x=360°

5x + 20= 360

5x = 360-20

5x = 340

x = 340/5

x = 68

First angle = 68°.

Second angle = x-10 = 68-10 = 58°.

Third angle = x+ 30 = 68+30 = 98°.

Fourth angle = 2x = 2× 68 = 136°.

The smallest angle is = 58°, second angle.

$\large \purple{✳ \: hope \: it \: help \: you ✳}$

Answer 2

Answer:

58

Step-by-step explanation:

The sum of quadrilateral is 360°.

So, x+ x-10+ x+30+2x=360°

5x + 20= 360

5x = 360-20

5x = 340

x = 340/5

x = 68

Smallest angle=x-10= 68 - 10= 58