Question

The angles of a quadrilateral are x0, (x-10)0, (x+30)0 and (2x)0, the smallest angle is equal to

Answer 1

Answer:

given angles(in degrees) = x,x-10,x=30,2x

sum of all angles o a quadrilateral is 360

=> x+x-10+x+30+2x= 360

=> 5x=20 = 360

=>5x= 340

=>x=68

smallest angle is x-10

i.e. 68-10=58 degrees

Step-by-step explanation:

Answer 2

Given,

The angles of quadrilaterals are x, x-10, x+30, 2x.

To find,

The smallest angle of the quadrilaterals.

Solution,

The sum of angles of a quadrilateral is always 360°.

Therefore, x+x-10+x+30+2x=360

5x+20 = 360

+20 which is on the left-hand side of the equation would be shifted to the right-hand side of the equation and its sign would change from +20 to -20.

Therefore, we get-

⇒  5x = 360-20

⇒  5x = 340

⇒  x = 340/5

⇒  x = 68°.

Hence, the angles of a quadrilateral are-

⇒ x = 68°

⇒  x - 10 = 68° - 10° = 58°

⇒  x + 30 = 68° + 30 = 98°

⇒  2x = 2(68°) = 136°

Hence, the smallest angle of the given quadrilateral is 68°.