The angles of a quadrilateral at(x-30)degree, (x-8)degree,3xdegree and (2x-10)degree.find x.
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Angles are ( x - 30 ), ( x - 8 ), 3x and ( 2x - 10 ).
Sum of all angles in a quadrilateral,
so
= > ( x - 30 ) + ( x - 8 ) + 3x + ( 2x - 10 ) = 360
Opening paranthesis
= > x - 30 + x - 8 + 3x + 2x - 10 = 360
Combining of like terms
= > x + x + 3x + 2x - 30 - 8 - 10 = 360
= > 7x - 48 = 360
= > 7x = 360 + 48
= > 7x = 408
= > x = 408/7
Henceforth value of x is 408/7
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