Question

the angles of a triangle are in AP.If the smallest angle is 50° find the other two angles

Answer 1

HEYA!
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Let the angles be a-d , a , a+d respectively { since they are in AP}

Now we have ,

$a - d + a + a + d = 180 \: \: (angle \: sum \: property) \\ \\ = > 3a = 180 \\ \\ = > a = 60 \:$
✨Hence the angles becomes 60 -d , 60 and 60 +d

✳Here , smallest angle = 60-d

Smallest angle given , : 50 degrees


60 - d = 50

-d = -10

d= 10
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Putting in the angles assumed ,

The measures of the angles becomes


50 , 60 and 70 degrees respectively.


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