Question

the angles of a triangle are in the ration 4:3:2,find the angle.​

Answer 1

Answer:

Find the angles of a triangle which are in the ratio 4: 3: 2 ... Let the measures of the given angles of the triangles be (4x)o, (3x)o and (2x)o respectively. So, the angle measures (4 × 20)o, (3 × 20)o, (2 × 20)o, i.e., 80o, 60o, 40o. Hence, the angles of the triangles are 80o, 60.

Answer 2

Given:

Ratio of angles of a triangle = 4:3:2

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Solution:

Let the first angle be 4x.

Let the second angle be 3x.

Let the third angle be 2x.

$\boxed {\sf {\purple {As\ we\ know\ that\ sum\ of\ all\ the\ angles\ of\ a\ triangle\ is\ 180°}}}$

So,

4x + 3x + 2x = 180°

9x = 180°

$x = \dfrac{180°}{9}$

$\boxed {\boxed {\sf {\green {x = 20°}}}}$

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Verification:

On substituting the value of x as 20° in the equation,

4x + 3x + 2x = 180°

4×20°+3×20°+2×20° = 180°

80°+60°+40° = 180°

80°+100° = 180°

180° = 180°

LHS = RHS

Hence Verified!

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Final answer:

• First angle = 4x

= 4×20°

= 80°

• Second angle = 3x

= 3×20°

= 60°

• Third angle = 2x

= 2×20°

= 40°

$\boxed {\sf {\pink {The\ angles\ of\ the\ triangle\ are\ 80°, 60°\ and\ 40°.}}}$