Question

The angles of a triangle are (x – 35)°, (x – 20)° and (x + 40)°.
Find the three angles.

Answer 1

(x-35)°+(x-20)°+(x+40)°=180(sum of the angles of a triangle is 180°).
3x-15°=180°
3x=180°+15°
3x=195°
x=195°/3
x=65°
first angle :(65-35)°=30°
second angle :(65-20)°=45°
third angle :=(65+40)°=105°
thank you hope it helps....

Answer 2

Hey

we know that the sum of angles of a triangle =180°
so


(x-35)°+(x-20)°+(x+40)°=180°
x°-35°+x°-20°+x°+40°=180°
3x°-55°+40°=180°
3x°-15°=180°
3x°=180°+15°
3x°=195°
x°=195/3
x°=65°

so angle 1st= (x-35)°=(65-35)°=30°
angle 2nd=(x-20)°=(65-20)°=45°
angle 3rd=(x+40)°=(65+40)°=105°

Hope it helps to you.