the angles of a triangle are (x-40)°, (x-20)° and [1x/2-10°]. Find the value of x .
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The sum of measures of angles of a triangles is 180 degrees
∴(x−40)+(x−20)+(x/2−10)=180 degree
∴5x/2−70degree=180degree
∴5x/2=250 degree
∴5x=500 degree
∴x=100 degree
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Answer:
The sum of measures of angles of a triangles is 180 degrees
∴(x−40)+(x−20)+(x/2−10)=180
o
∴5x/2−70
o
=180
o
∴5x/2=250
o
∴5x=500
o
∴x=100
o
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