Question

The angles of a triangle are (x-40)º, (x-20) and (x/2-10)
, find x.​

Answer 1

Sum of angles of a triangle is 180°

the angles are

(x-40)

(x-20)

(x/2 - 10).

Hence the

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5

⇒ x = 100

The Angles are

1)x-40 = 100 - 40 = 60

2)x - 20 = 100 - 20 = 80

3)x/2 - 10 = 100/2 - 10 = 40

Answer 2

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