The angles of a triangle are (x-40°),(x-20°) and (x/2-10)°. Find the value of x and then the angles of the triangle.
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sum of the angles in any triangle =180degree
x-40+x-20+x/2-10=180
x+x+x/2=180+40+20+10
5x/2=250
x=250* 2/5
x=50*2
x=100
first angle = x-40=100-40=60
second=x-20=100-20=80
third = x/2-10 = 100/2 -10= 50-10 =40
x-40+x-20+x/2-10=180
x+x+x/2=180+40+20+10
5x/2=250
x=250* 2/5
x=50*2
x=100
first angle = x-40=100-40=60
second=x-20=100-20=80
third = x/2-10 = 100/2 -10= 50-10 =40
mysticd:
ur welcome
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angles will be
60, 80,and 40
60, 80,and 40
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