the angles of a triangle are x-40degree, 2x+30 degree and x-10 degree find X and all the angles of triangle
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sum of all angles of triangle = 180 degree
x-40 + 2x+30 + x- 10 = 180
4x -20 = 180
x= 50 degree
x-40 = 50 -40 = 10 degree
2x+30 = 2×50 +30 = 130 degree
x-10 = 50-10 = 40 degree
x-40 + 2x+30 + x- 10 = 180
4x -20 = 180
x= 50 degree
x-40 = 50 -40 = 10 degree
2x+30 = 2×50 +30 = 130 degree
x-10 = 50-10 = 40 degree
Answered by
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angles of three triangle are (x - 40)° , (2x + 30)° and ( x - 10)° .
we know, sum of angles of three triangle is 180° .
(x - 40)° + (2x + 30)° + (x - 10)° = 180°
4x - 40° + 30° - 10° = 180°
4x - 20° = 180°
4x = 200° => x = 50°
hence, (x - 40)° = (50-40)° = 10°
(2x + 30)° = (2×50+30)° = 130°
(x - 10)° = (50 - 10)° = 40°
we know, sum of angles of three triangle is 180° .
(x - 40)° + (2x + 30)° + (x - 10)° = 180°
4x - 40° + 30° - 10° = 180°
4x - 20° = 180°
4x = 200° => x = 50°
hence, (x - 40)° = (50-40)° = 10°
(2x + 30)° = (2×50+30)° = 130°
(x - 10)° = (50 - 10)° = 40°
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