Question

the angles of a triangle measure the 3x ,3x+10,and 3x-10.find the value of x and calculate each other​

Answer 1

Step-by-step explanation:

a + b + c = 180 ( sum of all angles of triangle = 180 °)

3x + 3x + 10 + 3x -10 = 180°

9x + 0 = 180°

x = 180°/ 9

x = 20°

a = 3x = 3×20 =60°

b= 3x + 10 = 3 × 20 +10 = 70°

c = 3x - 10 = 3× 20 -10 = 50 °

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Answer 2

The angles of the triangle measure 60 degrees, 70 degrees, and 50 degrees.

In a triangle, the sum of the angles is always 180 degrees. Therefore, we can write an equation based on the given angles:

3x + (3x+10) + (3x-10) = 180

Simplifying the equation:

9x = 180

x = 20

Now we can use this value of x to calculate each angle:

Angle 1 = 3x = 3(20) = 60 degrees

Angle 2 = 3x + 10 = 3(20) + 10 = 70 degrees

Angle 3 = 3x - 10 = 3(20) - 10 = 50 degrees

Therefore, the angles of the triangle measure 60 degrees, 70 degrees, and 50 degrees.

For such more questions on triangle,

https://brainly.in/question/53150973

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