Question

The angles of depression of two ships from the top of a light house and on the same side of it are found to be 45° and 30° respectively. If the ships are 200 m apart, find the height of the light house.

Answer 1

Answer:

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AC is the height of the light house and 45 and 30 degree are the angles of depression . So now angleABC=30 angle ADC =45 degree. Now apply tan theta =opp/adj .so now here tan30= AC/BC ,we knew that the value of tan 30 is 1 by root 3 so we willget it as Bc = 200root 3 .similarly tan45=1 and now CD = 200m.Now here i we add these two we will get 200+200 root 3.

Answer 2

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AC is the height of the light house and 45 and 30 degree are the angles of depression . So now angleABC=30 angle ADC =45 degree. Now apply tan theta =opp/adj .so now here tan30= AC/BC ,we knew that the value of tan 30 is 1 by root 3 so we willget it as Bc = 200root 3 .similarly tan45=1 and now CD = 200m.Now here i we add these two we will get 200+200 root 3